"Sn" + 2 "HF" kepada "SnF" _2 + "H" _2 Berapa gram hidrogen dihasilkan daripada tindak balas 30.00 g "HF"?

Jawapan:

# 1.5g #

Penjelasan:

Pertama, kita memerlukan bilangan tahi lalat # "HF" # digunakan:

#n ("HF") = (m ("HF")) / (M_r ("HF")) = 30/20 = 3 /

# ((n ("HF"),:, ("H" _2)), (2,:, 1)) #

Oleh itu, kita perlu separuh bilangan tahi lalat:

#n ("H" _2) = 1.5 / 2 = 0.75mol #

#m ("H" _2) = n ("H" _2) M_r ("H" _2) = 0.75 * 2 = 1.5g #