Apakah derivatif fungsi f (x) = ln (ln ((x + 4) / ln (x ^ 2 + 4)?

Jawapan:

#f '(x) = (1 / (ln ((x + 4) / (ln (x ^ 2 + 4))))) () ^ 2 + 4) (ln (x ^ 2 + 4)) - (2x ^ 2 + 4x)) / ((x ^ 2 + 4) (ln (x ^

Penjelasan:

#f '(x) = (1 / (ln ((x + 4) / (ln (x ^ 2 + 4)))) (1 / ((x + 4) / (ln (x ^ (X + 4) (1) / ((x ^ 2 + 4)) (2x)) / ((ln (x ^ 2 + 4))) ^ 2) #

#f '(x) = (1 / (ln ((x + 4) / (ln (x ^ 2 + 4))))) (ln (x ^ 2 + 4) / ((x + 4))). ((ln (x ^ 2 + 4) - (2x ^ 2 + 4x) / ((x ^ 2 + 4))) / ((ln (x ^ 2 + 4)

#f '(x) = (1 / (ln ((x + 4) / (ln (x ^ 2 + 4))))) (batalkan (ln (x ^ 2 + 4) (x ^ 2 + 4) (ln (x ^ 2 + 4)) - (2x ^ 2 + 4x)) / ((x ^ 2 +) ^ batalkan (2))) #

#f '(x) = (1 / (ln ((x + 4) / (ln (x ^ 2 + 4))))) () ^ 2 + 4) (ln (x ^ 2 + 4)) - (2x ^ 2 + 4x)) / ((x ^ 2 + 4) (ln (x ^