Jawapan:
Bukti di bawah
Penjelasan:
Perhatikan bahawa
Bagaimanakah anda mengesahkan identiti sec ^ 2 (x / 2) = (2secx + 2) / (secx + 2 + cosx)?
Diperlukan untuk membuktikan: sec ^ 2 (x / 2) = (2secx + 2) / (secx + 2 + cosx) "Side Hand Right" = (2secx + 2) / (secx + 2 + cosx) / cosx => (2 * 1 / cosx + 2) / (1 / cosx + 2 + cosx) Sekarang, kalikan atas dan bawah oleh cosx => (cosx xx (2 * 1 / cosx + 2) (1 / cosx + 2 + cosx)) => (2 + 2cosx) / (1 + 2cosx + cos ^ 2x) Faktorkan bahagian bawah, => > 2 / (1 + cosx) Ingat identiti: cos2x = 2cos ^ 2x-1 => 1 + cos2x = 2cos ^ 2x Begitu juga: 1 + cosx = 2cos ^ 2 (x / 2) => 2 / (2cos ^ 2 (x / 2)) = 1 / cos ^ 2 (x / 2) = warna (biru) (sec ^ 2 (x / 2)) =
Bagaimanakah anda mengesahkan identiti sec ^ 4theta = 1 + 2tan ^ 2theta + tan ^ 4theta?
Bukti di bawah Pertama kita akan membuktikan 1 + tan ^ 2theta = sec ^ 2theta: sin ^ 2theta + cos ^ 2theta = 1 sin ^ 2theta / cos ^ 2theta + cos ^ 2theta / cos ^ 2theta = 1 / cos ^ 2theta tan ^ 2theta + 1 = (1 / costheta) ^ 2 1 + tan ^ 2theta = sec ^ 2theta Sekarang kita dapat membuktikan soalan anda: sec ^ 4theta = (sec ^ 2theta) ^ 2 = (1 + tan ^ 2theta) ^ 2 = ^ theta + tan ^ 4theta
Bagaimana anda mengesahkan identiti 3sec ^ 2thetatan ^ 2theta + 1 = sec ^ 6theta-tan ^ 6theta?
Lihat di bawah 3sec ^ 2thetatan ^ 2theta + 1 = sec ^ 6theta-tan ^ 6theta Right Side = sec ^ 6theta-tan ^ 6theta = (sec ^ 2theta) ^ 3- (tan ^ 2theta) ^ 3-> formula = (sec ^ 2theta-tan ^ 2theta) (sec ^ 4theta + sec ^ 2thetatan ^ 2theta + tan ^ 4theta) = 1 * (sec ^ 4theta + sec ^ 2thetatan ^ 2theta + tan ^ 4theta) = sec ^ 4theta + ^ 2thetatan ^ 2theta + tan ^ 4theta = sec ^ 2theta sec ^ 2 theta + sec ^ 2thetatan ^ 2theta + tan ^ 2theta tan ^ 2 theta = sec ^ 2theta (tan ^ 2theta + 1) + sec ^ 2thetatan ^ 2theta + tan ^ 2theta (sec ^ 2theta-1) = sec ^ 2thetatan ^ 2theta + sec ^ 2theta + sec ^ 2thetatan ^ 2theta + sec ^ 2theta