Jawapan:
Penjelasan:
Bagaimana anda membezakan f (x) = sqrt (cote ^ (4x) menggunakan peraturan rantai.?
(x) = (- 4e ^ (4x) csc ^ 2 (e ^ (4x)) (cot (e ^ (4x))) ^ (- 1/2) (x) = sqrt (cot (e ^ (4x)) = - (2e ^ (4x) csc ^ (x) = f (x)) = sqrt (g (x)) f '(x) = 1/2 * (g (x)) ^ (- 1/2) (g '(x)) = (g' (x) (g (x)) ^ (- 1/2)) / 2 g (x) = cot (e ^ (4x) (x) = cot (h (x)) g '(x) = - h' (x) csc ^ 2 (h (x) (x) = h (x) = j '(x) e ^ (j (x) = j (x) = 4x j' (x) = 4 h ' (X) = - 4e ^ (4x) csc ^ 2 (e ^ (4x)) f '(x) = (- 4e ^ (4x) csc ^ 2 (e ^ (4x) (cot (e ^ (4x))) ^ (- 1/2)) / 2 warna (putih) (f '(x)) = - (2e ^ (4x) csc ^ 2 (e ^ (4x))) / sqrt (cot (e ^ (4x))
Bagaimana anda membezakan sqrt ((x + 1) / (2x-1))?
F (x) = u ^ n f '(x) = n xx ((x (1) du) / dx xxu ^ (n-1) Dalam kes ini: sqrt ((x + 1) / (2x-1)) = ((x + 1) / (2x-1) n = 1/2, u = (x + 1) / (2x-1) d / dx = 1/2 xx (1xx (2x-1) - 2xx (x + 1) xx (x + 1) / (2x-1)) ^ (1 / 2-1) = 1 / 2xx (-3) / ((2x-1) ^ 2 xx ((x + 1) 1)) ^ (1 / 2-1) = - (3 (x + 1)) / (2 (2x-1) ^ 2 ((x + 1) / (2x-1)
Bagaimana anda membezakan f (x) = sqrt (ln (1 / sqrt (xe ^ x)) menggunakan peraturan rantai.?
Sekadar aturan rantai lagi dan lagi. f '(x) = e ^ x (1 + x) / 4sqrt ((xe ^ x) / (ln (1 / sqrt (xe ^ x)) (xe ^ x) ^ 3) f (x) = (sqrt (ln (1 / sqrt (xe ^ x)))) '= = 1 / (2sqrt (ln (1 / sqrt (xe ^ x))))) *) = 1 / (2sqrt (ln (1 / sqrt (xe ^ x))) * * sqrt (xe ^ x) (1 / sqrt (xe ^ x)) '= = sqrt (xe ^ x) / (2sqrt (ln (1 / sqrt (xe ^ x) (xe ^ x) / (2sqrt (ln (1 / sqrt (xe ^ x)))) ((xe ^ x) ^ - (1/2)) '= = sqrt (xe ^ x) / (2sqrt (ln (1 / sqrt (xe ^ x))) (- 1/2) ((xe ^ x) ^ - (3/2)) (xe ^ x) '= = sqrt (xe ^ x) / (4sqrt ( ln (1 / sqrt (xe ^ x)))) (xe ^ x) ^ - (3/2)) (xe ^ x) '= = sqrt (xe ^ x) / (4sqrt (ln (1