Apakah sudut n = 2x ^ 2-x-3-4 (x-1) ^ 2?

Apakah sudut n = 2x ^ 2-x-3-4 (x-1) ^ 2?
Anonim

Jawapan:

# "Vertex": (7/4, -7/8) #

Penjelasan:

# y = 2x ^ 2-x-3-4 (x-1) ^ 2 #

#y = 2x ^ 2-x-3-4x ^ 2 + 8x-4 #

#y = -2x ^ 2 + 7x - 7 #

#f (x) = ax ^ 2 + bx + c ": x vertex" = (-b) / (2a) #

# (- b) / (2a) = (-7) / (2 (-2) = 7/4 #

#y = -2 (7/4) ^ 2 + 7 (7/4) - 7 = (-7) / 8 #