Apakah tempoh f (theta) = tan ((5theta) / 12) - cos ((theta) / 4)?

Apakah tempoh f (theta) = tan ((5theta) / 12) - cos ((theta) / 4)?
Anonim

Jawapan:

# 24pi #

Penjelasan:

Tempoh #tan (5t) / 12) # --> # (12pi) / 5 #

Tempoh kos (t / 4) -> # 8pi #

Gandaan kurang biasa # ((12pi) / 5) dan (8pi) # --> # 24pi #

# ((12pi) / 5)..X.. (10) -> #24pi #

# (8pi) # … X …. (3) ….--> # 24pi #

Tempoh f (t) -> # 24pi #